Example Question - multiplication
Here are examples of questions we've helped users solve.
Multiplication Problem
<p>To solve \( 2 \times 2 \):</p> <p>1. Multiply the numbers:</p> <p> \( 2 \times 2 = 4 \)</p> <p>Therefore, the answer is 4.</p>
Calculating a Weighted Product
<p> To solve the equation, first express the fraction:</p> <p> \(\frac{9}{7} \times 32 \, \text{kg}\) </p> <p> Now, multiply the two values:</p> <p> \(\frac{9 \times 32}{7} \, \text{kg}\) </p> <p> Calculating \(9 \times 32 = 288\): </p> <p> \(\frac{288}{7} \, \text{kg} \approx 41.14 \, \text{kg}\) </p> <p> Thus, the solution is approximately \(41.14 \, \text{kg}\). </p>
Multiplication of Mixed Fraction and a Measurement
<p>Convert the mixed number \(9 \frac{7}{6}\) to an improper fraction:</p> <p>\(9 \frac{7}{6} = \frac{9 \times 6 + 7}{6} = \frac{54 + 7}{6} = \frac{61}{6}\)</p> <p>Now multiply with \(32 \, \text{kg}\):</p> <p>\(\frac{61}{6} \times 32 = \frac{61 \times 32}{6}\)</p> <p>Calculate \(61 \times 32 = 1952\), so:</p> <p>\(\frac{1952}{6}\)</p> <p>Now simplify:</p> <p>Divide \(1952\) by \(6\): \(1952 \div 6 = 325.3333\) (approximately)</p> <p>The final answer in kg is \(325.33 \, \text{kg}\) (rounded to two decimal places).</p>
Multiplication of Fractions and Weight
<p>First, express the mixed number as an improper fraction:</p> <p>\(9 \frac{7}{6} = \frac{9 \times 6 + 7}{6} = \frac{54 + 7}{6} = \frac{61}{6}\)</p> <p>Now multiply by \(32 \, \text{kg}\):</p> <p>\(\frac{61}{6} \times 32 = \frac{61 \times 32}{6} = \frac{1952}{6} = 325.33 \, \text{kg}\)</p> <p>The final result is approximately \(325.33 \, \text{kg}\).</p>
Calculate the Weight Using Fraction
<p>First, convert the mixed number \(3 \frac{1}{2}\) to an improper fraction:</p> <p>\(3 \frac{1}{2} = \frac{7}{2}\)</p> <p>Then, multiply by \(26 \, \text{kg}\):</p> <p>\(\frac{7}{2} \times 26 \, \text{kg} = \frac{7 \times 26}{2} \, \text{kg} = \frac{182}{2} \, \text{kg} = 91 \, \text{kg}\)</p> <p>The final answer is \(91 \, \text{kg}\).</p>
Finding the Value of an Expression
<p>First, calculate the multiplication: 16 × 5 = 80.</p> <p>Next, simplify the fraction: q/10.</p> <p>Now, the equation becomes: 80 × (q/10) = 8q.</p> <p>Therefore, the solution is 8q.</p>
Finding the Value of a Variable
<p>To solve for \( q \), start with the equation:</p> <p> \( 16 \times 5 \times \frac{q}{10} = \text{{value}} \)</p> <p>First, simplify the left side:</p> <p> \( 16 \times 5 = 80 \), hence:</p> <p> \( 80 \times \frac{q}{10} = \text{{value}} \)</p> <p>Next, multiply \( 80 \) by \( \frac{1}{10} \):</p> <p> \( 8q = \text{{value}} \)</p> <p>Finally, solve for \( q \):</p> <p> \( q = \frac{\text{{value}}}{8} \)</p>
Multiplication of Mixed Numbers and Improper Fractions
<p>Convert the mixed number to an improper fraction:</p> <p>2 \frac{1}{3} = \frac{2 \times 3 + 1}{3} = \frac{7}{3}</p> <p>Now, multiply:</p> <p>\frac{7}{3} \times \frac{4 \times 3 + 3}{7} = \frac{7}{3} \times \frac{15}{7}</p> <p>Cancel the 7s:</p> <p> \frac{15}{3} = 5</p> <p>Thus, the solution is 5.</p>
Finding the Value of a Variable
<p>To solve for \( q \), start with the equation:</p> <p>\( \frac{3}{8} \times 4 \times q = \text{blank} \)</p> <p>First, calculate \( \frac{3}{8} \times 4 \):</p> <p>\( \frac{3 \times 4}{8} = \frac{12}{8} = \frac{3}{2} \)</p> <p>Now substitute this into the equation:</p> <p>\( \frac{3}{2} \times q = \text{blank} \)</p> <p>Solving for \( q \):</p> <p>\( q = \frac{\text{blank}}{\frac{3}{2}} = \text{blank} \times \frac{2}{3} \)</p>
Multiplying Powers with Coefficients
<p>First, multiply the coefficients: \( 12 \times 8 \times \frac{3}{4} = 24 \times 3 = 72 \)</p> <p>Next, add the exponents of \( p \): \( 6 + 3 + 7 = 16 \)</p> <p>The final answer is \( 72p^{16} \)</p>
Basic Arithmetic Operations
<p>1. Calculate \( 35.6 - 27.92 \): </p> <p> \( 35.6 - 27.92 = 7.68 \) </p> <p>2. Calculate \( 35.6 + 5.67 \): </p> <p> \( 35.6 + 5.67 = 41.27 \) </p> <p>3. Calculate \( 56.78 \times 7.5 \): </p> <p> \( 56.78 \times 7.5 = 426.85 \) </p> <p>4. Calculate \( 91.8 \div 3.6 \): </p> <p> \( 91.8 \div 3.6 = 25.5 \) </p>
Division and Multiplication of Fractions
<p>To solve the expression \( \frac{2}{4} \div \frac{2}{16} \), we first rewrite the division as multiplication by the reciprocal:</p> <p>\( \frac{2}{4} \times \frac{16}{2} \)</p> <p>Now, we can simplify:</p> <p>\( \frac{2 \times 16}{4 \times 2} = \frac{32}{8} \)</p> <p>Next, simplify \( \frac{32}{8} \):</p> <p>Thus, the final answer is \( 4 \).</p>
Simple Fraction Multiplication
<p>\( \frac{4}{7} \times \frac{5}{2} = \frac{4 \times 5}{7 \times 2} \)</p> <p>\( = \frac{20}{14} \)</p> <p>\( = \frac{10}{7} \) (بعد اختصار الكسر بالقسمة على 2)</p>
Simple Algebraic Problem Involving Multiplication and Addition
<p>Vamos considerar o número desconhecido como \( x \).</p> <p>De acordo com o problema, Sam multiplica este número por 2 e então adiciona 3 ao produto, e o resultado dessa operação é 7. Logo, podemos expressar isso como uma equação: </p> <p>\( 2x + 3 = 7 \)</p> <p>Para resolver a equação, primeiro subtraímos 3 de ambos os lados:</p> <p>\( 2x + 3 - 3 = 7 - 3 \)</p> <p>\( 2x = 4 \)</p> <p>Agora dividimos ambos os lados por 2 para obter \( x \):</p> <p>\( \frac{2x}{2} = \frac{4}{2} \)</p> <p>\( x = 2 \)</p> <p>Portanto, o número que Sam escolheu é 2.</p>
Problem Involving Subtraction and Multiplication to Find a Number
<p>Vamos chamar o número desconhecido de \( x \).</p> <p>Segundo a questão, Lily subtrai 8 do número. Então, temos \( x - 8 \).</p> <p>Depois, ela multiplica a diferença por 3, ou seja \( 3(x - 8) \).</p> <p>É dado que o produto é 14, então temos a equação: \( 3(x - 8) = 14 \).</p> <p>Resolvendo a equação:</p> <p>\( 3(x - 8) = 14 \)</p> <p>\( 3x - 24 = 14 \)</p> <p>\( 3x = 14 + 24 \)</p> <p>\( 3x = 38 \)</p> <p>\( x = \frac{38}{3} \)</p> <p>\( x = 12\frac{2}{3} \)</p>
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