Question - Solving Area Problems with Mixed Numbers
Solution:
The image shows two mixed numbers: 4 and 5/6 feet by 2 and 1/3 feet. To solve problems like these, typically involving the dimensions of an area, you multiply the length by the width.First, convert each mixed number to an improper fraction:\[ 4 \frac{5}{6} = \frac{4 \times 6 + 5}{6} = \frac{24 + 5}{6} = \frac{29}{6} \]\[ 2 \frac{1}{3} = \frac{2 \times 3 + 1}{3} = \frac{6 + 1}{3} = \frac{7}{3} \]Now multiply the two improper fractions together:\[ \frac{29}{6} \times \frac{7}{3} = \frac{29 \times 7}{6 \times 3} \]\[ = \frac{203}{18} \]Now we will convert this improper fraction back to a mixed number and simplify if necessary:\[ \frac{203}{18} = 11 \frac{7}{18} \](11 is the whole number part, because 203 divided by 18 is 11 with a remainder of 7.)So, the area covered is 11 and 7/18 square feet.
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