Solving Area Problems with Mixed Numbers
The image shows two mixed numbers: 4 and 5/6 feet by 2 and 1/3 feet. To solve problems like these, typically involving the dimensions of an area, you multiply the length by the width.
First, convert each mixed number to an improper fraction:
\[ 4 \frac{5}{6} = \frac{4 \times 6 + 5}{6} = \frac{24 + 5}{6} = \frac{29}{6} \]
\[ 2 \frac{1}{3} = \frac{2 \times 3 + 1}{3} = \frac{6 + 1}{3} = \frac{7}{3} \]
Now multiply the two improper fractions together:
\[ \frac{29}{6} \times \frac{7}{3} = \frac{29 \times 7}{6 \times 3} \]
\[ = \frac{203}{18} \]
Now we will convert this improper fraction back to a mixed number and simplify if necessary:
\[ \frac{203}{18} = 11 \frac{7}{18} \]
(11 is the whole number part, because 203 divided by 18 is 11 with a remainder of 7.)
So, the area covered is 11 and 7/18 square feet.
