Question - Solving a German Math Problem on Place Values and Subtraction

Let's denote the unknown number as X where X has units in the form of thousands (T), hundreds (H), tens (Z), and ones (E). According to the question, X can be written in the form of THZE. We will solve each part of the question separately.

(a) For the first part, we are given that:

X has 2 tens of thousands, hence T = 2

Half as many tens as tens of thousands, hence Z = \frac{T}{2} = \frac{2}{2} = 1

Twice as many ones as thousands, hence E = 2 \cdot T = 2 \cdot 2 = 4

Seven hundreds, hence H = 7

Therefore, X = 21714

(b) If we subtract 3 from the tens place, 3 from the hundreds place, and 4 from the thousands place in X, the result is 2086. Now let's adjust X accordingly:

New thousands (T) = 2 - 4 = -2 (which is not possible because a negative number of thousands does not make sense, so there's a logical contradiction here. The number we obtained from part (a) cannot satisfy the condition in part (b). We need to revise our assumptions or there might be a misinterpretation of the question. Since we cannot have T < 0, the problem might be structured incorrectly or the question might be missing some details. Therefore, we've found an issue at this stage and cannot proceed with the calculation. Given this ambiguity, a correct answer cannot be calculated at this time for part (b).)

(c) Without a valid number from parts (a) or (b), we cannot proceed to divide it by 5 for part (c), as the preceding parts contain a logical contradiction or an inaccuracy in problem setup or interpretation.

Due to the contradiction encountered in part (b) of the question, we need to check the original problem statement for any errors or missing information to provide a proper solution.