CamTutor

Example Question - elementary math

Here are examples of questions we've helped users solve.

Fraction Simplification

La fracción dada es \( \frac{8}{10} \). Para simplificar la fracción a su forma más simple, necesitamos dividir tanto el numerador como el denominador por su máximo común divisor (MCD). El MCD de 8 y 10 es 2. Dividimos el numerador y el denominador por 2: \( \frac{8 \div 2}{10 \div 2} = \frac{4}{5} \) Por lo tanto, la fracción simplificada es \( \frac{4}{5} \).

Simple Multiplication Problem

To solve the multiplication problem, multiply the two numbers: 2 \times 9 = 18

Solving a German Math Problem on Place Values and Subtraction

Let's denote the unknown number as X where X has units in the form of thousands (T), hundreds (H), tens (Z), and ones (E). According to the question, X can be written in the form of THZE. We will solve each part of the question separately. (a) For the first part, we are given that: X has 2 tens of thousands, hence T = 2 Half as many tens as tens of thousands, hence Z = \frac{T}{2} = \frac{2}{2} = 1 Twice as many ones as thousands, hence E = 2 \cdot T = 2 \cdot 2 = 4 Seven hundreds, hence H = 7 Therefore, X = 21714 (b) If we subtract 3 from the tens place, 3 from the hundreds place, and 4 from the thousands place in X, the result is 2086. Now let's adjust X accordingly: New thousands (T) = 2 - 4 = -2 (which is not possible because a negative number of thousands does not make sense, so there's a logical contradiction here. The number we obtained from part (a) cannot satisfy the condition in part (b). We need to revise our assumptions or there might be a misinterpretation of the question. Since we cannot have T < 0, the problem might be structured incorrectly or the question might be missing some details. Therefore, we've found an issue at this stage and cannot proceed with the calculation. Given this ambiguity, a correct answer cannot be calculated at this time for part (b).) (c) Without a valid number from parts (a) or (b), we cannot proceed to divide it by 5 for part (c), as the preceding parts contain a logical contradiction or an inaccuracy in problem setup or interpretation. Due to the contradiction encountered in part (b) of the question, we need to check the original problem statement for any errors or missing information to provide a proper solution.

Fill in the Blank for a Simple Multiplication Equation

\[ \begin{align*} 6 \times 9 &= 6 \times (5 + \boxed{4}) \\ 54 &= 6 \times 9 \\ 54 &= 6 \times (5 + 4) \\ 54 &= 6 \times 5 + 6 \times 4 \\ 54 &= 30 + 24 \\ 54 &= 54 \\ \text{Hence, the missing number is } \boxed{4}. \end{align*} \]

Solving Arithmetic Operations Involving Addition, Subtraction, Multiplication, and Division

Para la pregunta 3, aplicamos el orden de las operaciones, también conocido como PEMDAS/BODMAS (Paréntesis, Exponentes, Multiplicación y División, Adición y Sustracción): \( 24 - 8 \div 2 + 9 - 10 \) Primero realizamos la división: \( 24 - 4 + 9 - 10 \) Después, realizamos las operaciones de izquierda a derecha, comenzando con la resta y luego la suma: \( 20 + 9 - 10 \) \( 29 - 10 \) \( 19 \) Por lo tanto, la solución para la pregunta 3 es 19. Para la pregunta 4, nuevamente aplicamos el orden de las operaciones: \( 10 + 3 \times 4 - 9 \) Primero realizamos la multiplicación: \( 10 + 12 - 9 \) Luego, realizamos las operaciones de suma y resta de izquierda a derecha: \( 22 - 9 \) \( 13 \) Así, la solución para la pregunta 4 es 13.

Solving a Distance Problem

선자는 물 위에 뜬 판 위에 1000리터 물까지 싣고 갈 수 있다고 그 물고기의 '솔직히' 말하자면 1200리터의 무게까지 실을 수 있다고 합니다. 해결 방법은 다음과 같습니다: 1. 선자가 실을 수 있는 최대 무게를 찾기 위해서 '솔직히' 말한 무게에서 실제로 실을 수 있는 무게를 빼줍니다. \[ 1200리터 - 1000리터 = 200리터 \] 2. 선자는 200리터 더 실을 수 있다고 합니다.

Basic Division Exercises

a. \[ 132 \div 3 = 44 \] b. \[ 938 \div 3 = 312 \quad \text{Resto} \quad 2 \] c. \[ 780 \div 4 = 195 \] d. \[ 292 \div 6 = 48 \quad \text{Resto} \quad 4 \] e. \[ 463 \div 7 = 66 \quad \text{Resto} \quad 1 \] f. \[ 539 \div 7 = 77 \] g. \[ 1470 \div 5 = 294 \] h. \[ 2089 \div 4 = 522 \quad \text{Resto} \quad 1 \] i. \[ 258 \div 3 = 86 \]