Question - Solution to Subtracting Mixed Numbers
Solution:
To solve the equation given in the image, we must subtract the two mixed numbers.The first mixed number is $$6 \frac{11}{12}$$ and the second one is $$4 \frac{1}{3}$$. Before we subtract, we should convert these mixed numbers into improper fractions:For $$6 \frac{11}{12}$$:$$6 \times 12 = 72$$, then add $$11$$ for the numerator: $$72 + 11 = 83$$. This gives us $$ \frac{83}{12} $$.For $$4 \frac{1}{3}$$:$$4 \times 3 = 12$$, then add $$1$$ for the numerator: $$12 + 1 = 13$$. This gives us $$ \frac{13}{3} $$.Now let's subtract $$ \frac{83}{12} - \frac{13}{3}$$.First, we need to find a common denominator. The lowest common denominator for $$12$$ and $$3$$ is $$12$$. Convert $$ \frac{13}{3} $$ to have a denominator of $$12$$:$$ \frac{13}{3} $$ can be changed by multiplying both the numerator and denominator by $$4$$, because $$12$$ is $$4$$ times $$3$$. So, $$ \frac{13}{3} $$ becomes $$ \frac{13 \times 4}{3 \times 4} $$, which is $$ \frac{52}{12} $$.Now we have:$$ \frac{83}{12} - \frac{52}{12} = \frac{83 - 52}{12} = \frac{31}{12} $$.This improper fraction can be converted back to a mixed number. $$31$$ divided by $$12$$ gives $$2$$ with a remainder of $$7$$, hence the mixed number is $$2 \frac{7}{12}$$.So the answer to the subtraction is $$2 \frac{7}{12}$$, which is the whole number 2 plus the fraction $$ \frac{7}{12} $$. Since the question seems to ask for a whole number, the answer is $$2$$.
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