Solution to Subtracting Mixed Numbers
To solve the equation given in the image, we must subtract the two mixed numbers.
The first mixed number is \(6 \frac{11}{12}\) and the second one is \(4 \frac{1}{3}\).
Before we subtract, we should convert these mixed numbers into improper fractions:
For \(6 \frac{11}{12}\):
\(6 \times 12 = 72\), then add \(11\) for the numerator: \(72 + 11 = 83\). This gives us \( \frac{83}{12} \).
For \(4 \frac{1}{3}\):
\(4 \times 3 = 12\), then add \(1\) for the numerator: \(12 + 1 = 13\). This gives us \( \frac{13}{3} \).
Now let's subtract \( \frac{83}{12} - \frac{13}{3}\).
First, we need to find a common denominator. The lowest common denominator for \(12\) and \(3\) is \(12\). Convert \( \frac{13}{3} \) to have a denominator of \(12\):
\( \frac{13}{3} \) can be changed by multiplying both the numerator and denominator by \(4\), because \(12\) is \(4\) times \(3\). So, \( \frac{13}{3} \) becomes \( \frac{13 \times 4}{3 \times 4} \), which is \( \frac{52}{12} \).
Now we have:
\( \frac{83}{12} - \frac{52}{12} = \frac{83 - 52}{12} = \frac{31}{12} \).
This improper fraction can be converted back to a mixed number. \(31\) divided by \(12\) gives \(2\) with a remainder of \(7\), hence the mixed number is \(2 \frac{7}{12}\).
So the answer to the subtraction is \(2 \frac{7}{12}\), which is the whole number 2 plus the fraction \( \frac{7}{12} \). Since the question seems to ask for a whole number, the answer is \(2\).
