Question - Quadratic Equation Solution
mathsolving quadratic equationsquadratic formulaquadratic equation solutionroots of quadratic equation
Solution:
The given equation is a quadratic equation of the form ax^2 + bx + c = 0. To solve for x, we can use the quadratic formula:x = [-b ± sqrt(b^2 - 4ac)] / (2a)For our given equation:3x^2 + 5x - 2 = 0Here, a = 3, b = 5, and c = -2. Plugging these values into the quadratic formula gives us:x = [-5 ± sqrt(5^2 - 4 * 3 * (-2))] / (2 * 3)x = [-5 ± sqrt(25 + 24)] / 6x = [-5 ± sqrt(49)] / 6x = [-5 ± 7] / 6This gives us two possible solutions for x:x = (-5 + 7) / 6 = 2 / 6 = 1/3orx = (-5 - 7) / 6 = -12 / 6 = -2Therefore, the solutions for x are x = 1/3 or x = -2.
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