Question - Pattern of Increasing Blocks and Squares
Solution:
The image depicts three cases of a sequence of blocks, each adding more blocks than the previous one. To solve for the number of squares in Case 10, we should first identify a pattern.Case 1 has 1 block.Case 2 has 4 blocks (1 + 3).Case 3 has 9 blocks (1 + 3 + 5).We can observe that each case is the sum of consecutive odd numbers starting from 1. Let's verify this with the cases provided:- Case 1: 1 (which is 1^2)- Case 2: 1 + 3 = 4 (which is 2^2)- Case 3: 1 + 3 + 5 = 9 (which is 3^2)It seems that each case number squared gives the number of blocks in that case. So, for Case 10, the number of blocks would be $$10^2$$ or 100 blocks.Using this pattern, the answer for Case 10 is 100 squares.
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