Pattern of Increasing Blocks and Squares
The image depicts three cases of a sequence of blocks, each adding more blocks than the previous one. To solve for the number of squares in Case 10, we should first identify a pattern.
Case 1 has 1 block.
Case 2 has 4 blocks (1 + 3).
Case 3 has 9 blocks (1 + 3 + 5).
We can observe that each case is the sum of consecutive odd numbers starting from 1. Let's verify this with the cases provided:
- Case 1: 1 (which is 1^2)
- Case 2: 1 + 3 = 4 (which is 2^2)
- Case 3: 1 + 3 + 5 = 9 (which is 3^2)
It seems that each case number squared gives the number of blocks in that case. So, for Case 10, the number of blocks would be \(10^2\) or 100 blocks.
Using this pattern, the answer for Case 10 is 100 squares.
