Question - Unit Conversion Practice Problems

Solution:

\textbf{a) }\dfrac{5}{2}h \ \text{(in min)}

\dfrac{5}{2}h = \dfrac{5}{2} \times 60\ \text{min} = 150 \ \text{min}

\textbf{b) }\dfrac{3}{4}d \ \text{(in a)}

\dfrac{3}{4}d = \dfrac{3}{4} \times 1\ \text{a} = \dfrac{3}{4}\ \text{a}

\textbf{c) }\dfrac{6}{25}kg \ \text{(in g)}

\dfrac{6}{25}kg = \dfrac{6}{25} \times 1000\ \text{g} = 240\ \text{g}

\textbf{d) }\dfrac{3}{5}m^3 \ \text{(in dm$^3$)}

\dfrac{3}{5}m^3 = \dfrac{3}{5} \times 1000\ \text{dm}^3 = 600\ \text{dm}^3

\textbf{e) }\dfrac{3}{50}kg \ \text{(in g)}

\dfrac{3}{50}kg = \dfrac{3}{50} \times 1000\ \text{g} = 60\ \text{g}

\textbf{f) }\dfrac{2}{3}m \ \text{(in mm)}

\dfrac{2}{3}m = \dfrac{2}{3} \times 1000\ \text{mm} = 666.67\ \text{mm}

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