Question - Solving an Algebraic Equation Involving Basic Arithmetic Operations

The image displays an equation with a missing number which needs to be found:

\( (5 \times 8) + (\boxed{?} \times 8) = 40 + \boxed{?} \)

Since \( 5 \times 8 = 40 \), the equation simplifies to:

\( 40 + (\boxed{?} \times 8) = 40 + \boxed{?} \)

To find the missing number, let's denote it as \( x \):

\( 40 + (x \times 8) = 40 + x \)

Subtract \( 40 \) from both sides:

\( (x \times 8) = x \)

Divide both sides by \( x \) (assuming \( x \neq 0 \)):

\( 8 = 1 \)

This leads to a contradiction, as \( 8 \) does not equal \( 1 \). The problem seems to be constructed erroneously, as the equation provided does not hold true for any real number \( x \). We would need additional information or a correction to the equation to proceed.