Solution:
The image shows a set of cards with numbers from 2 through 9. The question asks for the probability of picking a 6 and then picking a 5.To solve this problem, we need to calculate the probability of picking a 6 first, and then, given that a 6 has been picked, the probability of then picking a 5.The total number of cards is 8 (2 through 9). The probability of picking a 6 first is 1 out of 8, because there is only one 6 in the set of cards.After picking a 6, there are 7 cards left. The probability of picking a 5 from the remaining cards is 1 out of 7, because there is only one 5 in the remaining set of cards.The probability of both events happening in sequence (picking a 6 and then picking a 5) is the product of the probabilities of each individual event happening:Probability of picking a 6 and then a 5 = (Probability of picking a 6) × (Probability of picking a 5 given a 6 was picked)= (1/8) × (1/7)= 1/56So the probability of picking a 6 and then picking a 5 is 1/56.