Question - Mathematical Expression Evaluation and X Calculation
Solution:
I'll help you solve each question individually.For question 2:To make the expression $$2 \times 3 + 3 = 3$$ correct, we need to insert brackets in such a way that it respects the order of operations and the equation balances. We can insert the brackets around "3 + 3":$$2 \times (3 + 3) = 3$$Now, let's evaluate the expression inside the brackets:$$2 \times 6 = 3$$But this equation $$2 \times 6 = 3$$ is not correct since $$2 \times 6$$ equals $$12$$, not $$3$$. Therefore, there's no way to insert brackets to make the original expression correct. It's possible that there's a typo or the exercise intends to challenge the student's understanding that some expressions with incorrect relationships cannot be made correct merely with bracket placement.For question 3:a. $$\frac{3}{36} = \frac{x}{36}$$To solve for $$x$$, we can cross-multiply:$$36 \times x = 3 \times 36$$$$36x = 108$$Divide both sides by 36:$$x = \frac{108}{36}$$Simplify the fraction:$$x = 3$$b. $$3 = \frac{36}{x}$$To solve for $$x$$, multiply both sides by $$x$$ and divide both sides by 3:$$3x = 36$$Divide by 3:$$x = \frac{36}{3}$$$$x = 12$$Therefore, $$x = 12$$.
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