Question - Finding Consecutive Whole Numbers of Square Root
Solution:
The image shows an inequality with a square root: $$ < \sqrt{78} < $$. We need to find two consecutive whole numbers between which $$\sqrt{78}$$ is located.First, let's find the whole number square roots closest to 78:- $$8^2 = 64$$- $$9^2 = 81$$Since 64 is less than 78 and 81 is greater than 78, we know that $$8 < \sqrt{78} < 9$$.Therefore, the two blanks should be filled with the numbers 8 and 9 to show this inequality correctly: $$8 < \sqrt{78} < 9$$.
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