Example Question - consecutive whole numbers
Here are examples of questions we've helped users solve.
Finding Consecutive Whole Numbers for Square Root of 83
The image shows an inequality with a square root of 83 surrounded by two empty boxes, one before and one after the square root, connected by less-than signs. The task is to find two consecutive whole numbers between which the square root of 83 lies. We know that the square root of 81 is 9 and the square root of 100 is 10. Since 83 is between 81 and 100, the square root of 83 will be between the square roots of these two perfect squares. Specifically: 9 < √83 < 10 Therefore, the two consecutive whole numbers that the square root of 83 lies between are 9 and 10. Hence, the boxes should be filled with the numbers 9 and 10, in that order.
Solving Inequality with Square Root
The given image depicts an inequality with a square root in the center: two blank boxes with less than signs around the square root of 104, written as "< √104 <". To solve this, we need to find two consecutive whole numbers between which the square root of 104 falls. Since we know that \(10^2 = 100\) and \(11^2 = 121\), the square root of 104 must be greater than 10 but less than 11 because 104 falls between 100 and 121. Therefore, the correct numbers to place in the boxes are 10 and 11. The completed inequality should read "10 < √104 < 11".
Finding Consecutive Whole Numbers of Square Root
The image shows an inequality with a square root: \( < \sqrt{78} < \). We need to find two consecutive whole numbers between which \(\sqrt{78}\) is located. First, let's find the whole number square roots closest to 78: - \(8^2 = 64\) - \(9^2 = 81\) Since 64 is less than 78 and 81 is greater than 78, we know that \(8 < \sqrt{78} < 9\). Therefore, the two blanks should be filled with the numbers 8 and 9 to show this inequality correctly: \(8 < \sqrt{78} < 9\).
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