Question - Finding Angle Measurement in Shifted Triangle

Solution:

In the given figure, there is a triangle APB with a 45° angle at A. It's stated that point A is shifted to point B along the ray PX such that PB = 2PA. We're asked to find the measure of ∠BPY.When point A is moved to point B, since PB is twice PA, triangle PBY will be an isosceles triangle where PB = PY. Therefore, the angles opposite the equal sides (PB and PY) will also be equal. Let's denote the measure of these angles as ∠PBY and ∠BPY, respectively.Because the sum of angles in a triangle is always equal to 180°, we can use this rule to find the measure of ∠BPY.For triangle PBY:∠PBY + ∠BPY + ∠B = 180°Since ∠PBY and ∠BPY are equal (isosceles triangle), we can say:2∠BPY + 45° = 180°Now, we solve for ∠BPY:2∠BPY = 180° - 45°2∠BPY = 135°Dividing both sides by 2 gives us:∠BPY = 135° / 2∠BPY = 67.5°So, the measure of ∠BPY is 67.5°, which is greater than 45°.The correct answer is:a) Greater than 45°

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