Given that the highest common factor (HCF) of 20 and p is 10, we have:
Factors of 20: 1, 2, 4, 5, 10, 20. The common factor with p must include 10.
To satisfy the HCF condition, p must include the factor 10. Therefore, p could be 10, 20, or another multiple of 10.
Given that the lowest common multiple (LCM) of 20 and p is 60, we calculate:
LCM(20, p) = (20 * p) / HCF(20, p)
Setting the equation for LCM:
(20 * p) / 10 = 60
20p = 600
p = 30
The smallest possible value of p is therefore:
p = 30
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