The derivative of \(y = 2t^4 - 10t^2 + 13t\) with respect to \(t\) is calculated by differentiating each term separately.
The derivative of the first term \(2t^4\) is \(8t^3\).
The derivative of the second term \(-10t^2\) is \(-20t\).
The derivative of the third term \(13t\) is \(13\).
Therefore, the derivative \( \frac{dy}{dt} = 8t^3 - 20t + 13 \).
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