\( \int \frac{3}{x} dx \neq 3 \int \frac{1}{x} dx \)
Let's solve the integral on the left side:
\( \int \frac{3}{x} dx = 3 \int \frac{1}{x} dx \)
Since \( \int \frac{1}{x} dx = \ln|x| + C \), where C is the constant of integration, we have:
\( 3 \int \frac{1}{x} dx = 3(\ln|x| + C) = 3\ln|x| + C' \)
So, the equality given in the question is incorrect, because:
\( \int \frac{3}{x} dx = 3\ln|x| + C' \)
And not:
\( 3 \int \frac{1}{x} dx = 9\ln|x| + C' \)
There seems to be a misunderstanding or typo in the provided equality.
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