Question - Calculation of Cylinder Dimensions Using Given Volume

Solution:

Let the height of the cylinder be \( h \) and the radius be \( r \). The volume \( V \) of a cylinder is given by \( V = \pi r^2 h \). The circumference \( C \) of the base of the cylinder is given by \( C = 2\pi r \). We are given: \( V = 12,936 \) cm\(^3\) \( \pi = \frac{22}{7} \) Firstly, we express \( r \) in terms of \( C \):

\( C = 2\pi r \Rightarrow r = \frac{C}{2\pi} \)

Substitute \( r \) into the volume formula and solve for \( h \):

\( V = \pi \left(\frac{C}{2\pi}\right)^2 h \)

\( 12,936 = \frac{22}{7} \left(\frac{C}{2 \cdot \frac{22}{7}}\right)^2 h \)

\( 12,936 = \frac{22}{7} \left(\frac{C}{44/7}\right)^2 h \)

\( 12,936 = \frac{22}{7} \left(\frac{7C}{44}\right)^2 h \)

\( 12,936 = \frac{22}{7} \left(\frac{C}{44/7}\right)^{\!2} h \)

\( 12,936 = \frac{22}{7} \left(\frac{C}{4}\right)^{\!2} h \)

\( 12,936 = \frac{22}{7} \cdot \frac{C^2}{16} \cdot h \)

\( 12,936 \cdot \frac{16}{22} = C^2 h \)

\( 12,936 \cdot \frac{16}{22} = C^2 h \)

\( 12,936 \cdot \frac{7 \cdot 16}{22} = 7C^2 h \)

\( 12,936 \cdot \frac{112}{22} = 7C^2 h \)

Now, let's solve for \( h \) in terms of \( C \):

\( h = \frac{12,936 \cdot \frac{112}{22}}{7C^2} \)

\( h = \frac{12,936 \cdot 112}{22 \cdot 7C^2} \)

Finally, we substitute the given value of the volume to find \( h \):

\( h = \frac{12,936 \cdot 112}{22 \cdot 7C^2} \)

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