Solution:
The question displayed in the image asks for the probability of picking an even number first and then picking an 8 when drawing cards labeled with the numbers 7, 8, and 9. Since the problem states that the card is put back before the second draw, the events are independent.To find the probability of both events happening, we calculate the probability of each event separately and then multiply them together.The probability of drawing an even number (which could only be the 8 in this case) on the first draw is 1 out of 3, since there is one even number and three cards overall.The probability of drawing an 8 on the second draw is again 1 out of 3, because after replacing the card, all three cards are available for selection again.Therefore, the combined probability is:Probability of even number (8) then an 8 =(1/3) * (1/3) =1/9The answer, as a simplified fraction, is 1/9.