The pressure \( P \) can be calculated using the relation:
\[ P = \frac{F}{A} \]where:
\( F \) is the force exerted by the tourist, and
\( A \) is the total contact area of the snow-shoes with the snow.
The force exerted by the tourist due to gravity (weight) is:
\[ F = m \cdot g \]The mass \( m \) of the tourist is given as 60 kg, and gravitational force \( g \) is 10 N/kg, so:
\[ F = 60 \text{ kg} \cdot 10 \text{ N/kg} = 600 \text{ N} \]The total area \( A \) is given as 0.6 m².
Now we can calculate the pressure \( P \):
\[ P = \frac{600 \text{ N}}{0.6 \text{ m}^2} = 1000 \text{ Pa} \]So, the correct answer is:
\( \boxed{D. 1000 \text{ Pa}} \)
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