Solution:
To find the height of the trapezoid, we can use the formula for the area of a trapezoid:\[ \text{Area} = \frac{1}{2}(b_1 + b_2)h \]where:- $$ b_1 $$ and $$ b_2 $$ are the lengths of the two parallel bases,- $$ h $$ is the height.From the given problem, we have:- $$ b_1 = 8 \text{ mm} $$- $$ b_2 = 6 \text{ mm} $$- Area = $$ 35 \text{ mm}^2 $$Now, let's plug in the values and solve for $$ h $$:\[ 35 = \frac{1}{2}(8 + 6)h \]\[ 35 = \frac{1}{2}(14)h \]\[ 35 = 7h \]\[ h = 35 \div 7 \]\[ h = 5 \text{ mm} \]So, the height of the trapezoid is 5 mm.