Question - Calculating Distance Traveled by an Accelerating Car from Rest

The distance traveled by an object under constant acceleration can be found using the equation:

\[ s = ut + \frac{1}{2}at^2 \]

where:

\[ u \] is the initial velocity (in this case, 0 m/s, since the car starts from rest),

\[ a \] is the constant acceleration (3 m/s^2), and

\[ t \] is the time (4 seconds).

Plugging in the values, we get:

\[ s = (0) \cdot 4 + \frac{1}{2} \cdot 3 \cdot (4)^2 \]

\[ s = 0 + \frac{1}{2} \cdot 3 \cdot 16 \]

\[ s = 0 + \frac{1}{2} \cdot 48 \]

\[ s = 24 \text{ meters} \]

Thus, the distance traveled by the car is 24 meters.