Example Question - median
Here are examples of questions we've helped users solve.
Comparing Battery Life Medians from Cellphone Models
<p>Para encontrar la solución, primero debemos calcular la mediana de las duraciones de la batería para cada modelo de celular. La mediana es el valor central de un conjunto de números ordenados.</p> <p>Modelo X:</p> <p>1. Ordenamos las duraciones de la batería del Modelo X: 550, 560, 570, 600, 620.</p> <p>2. La mediana será el valor central, que es 570 minutos.</p> <p>Modelo Y:</p> <p>1. Ordenamos las duraciones de la batería del Modelo Y: 520, 540, 670, 680, 690.</p> <p>2. La mediana será el valor central, que es 670 minutos.</p> <p>Modelo Z:</p> <p>1. Ordenamos las duraciones de la batería del Modelo Z: 520, 550, 550, 570, 710.</p> <p>2. La mediana será el valor que se encuentra en el centro, que es 550 minutos.</p> <p>Ahora, comparando las medianas:</p> <p>Modelo X: 570 minutos</p> <p>Modelo Y: 670 minutos</p> <p>Modelo Z: 550 minutos</p> <p>Con estos resultados, podemos responder a la afirmación de la opción A:</p> <p>A. "El modelo Z tiene una mediana igual a la del modelo X y menor que la del modelo Y."</p> <p>La afirmación es incorrecta porque la mediana del modelo Z (550 minutos) no es igual a la mediana del modelo X (570 minutos), y es menor que la del modelo Y (670 minutos).</p>
Understanding Statistical Concept: Median
Từ cái hình bạn vừa cung cấp, câu hỏi đang hỏi về một khái niệm thống kê, cụ thể là: "Khi dữ liệu thể hiện lượng các giá trị ngoại biên, số liệu nào sau đây được sử dụng để đánh giá mức độ tập trung hay phân tán của dữ liệu?" Các lựa chọn cho câu hỏi này là: A. Số trời B. Số trung vị C. Tỉ phần vị trí nhất. D. Số trung bình Câu trả lời đúng cho câu hỏi này là lựa chọn B, Số trung vị. Số trung vị là số liệu thống kê mô tả giá trị mà ở đó một nửa dữ liệu mẫu nằm trên giá trị đó và một nửa còn lại nằm dưới nó. Số trung vị không bị ảnh hưởng bởi các giá trị ngoại biên hoặc cực đoan, do đó nó là một số liệu thích hợp để đánh giá mức độ tập trung của dữ liệu khi dữ liệu có sự phân tán lớn hoặc có các giá trị ngoại biên.
Calculating Quartiles
To solve for the lower quartile, median, and upper quartile, you first need to arrange the data in ascending order, which appears to be already done in the image: 74, 76, 76, 78, 78, 79, 79. The median (or second quartile) is the middle number of a data set that's been arranged in order, and since there are seven numbers, the middle one is the fourth one: 78. For odd-numbered data sets, the lower quartile (or first quartile, Q1) is the median of the first half of the data not including the overall median. The first half of the data is 74, 76, 76, so the lower quartile is the middle of these three numbers, which is 76. The upper quartile (or third quartile, Q3) is the median of the second half of the data not including the overall median. The second half of the data is 78, 79, 79, so the upper quartile is the middle of these three numbers, which is 79. Therefore, the lower quartile is 76, the median is 78, and the upper quartile is 79.
Understanding Quartiles and Median
To solve for the lower quartile, median, and upper quartile, we need to understand that these are measures of central tendency and dispersion within a dataset. 1. **Lower quartile (Q1)**: This is the median of the first half of the dataset. Since there are five data points, we divide the dataset into two parts, with the median being the third number. For the first half (2, 6, 6), the lower quartile is the median of these, which is 6. 2. **Median**: This is the middle value of the dataset when it is ordered. Since the dataset (2, 6, 6, 7, 9) is already ordered and has an odd number of data points, the median is the middle number, which is 6. 3. **Upper quartile (Q3)**: This is the median of the second half of the dataset. For the second half (6, 7, 9), the upper quartile is the median of these, which is 7. So, your answers are: Lower quartile (Q1) = 6 Median = 6 Upper quartile (Q3) = 7
Statistical Quartiles Calculation
The image shows a list of numbers: 31, 33, 35, 57, 80, 87. To find the lower quartile, median, and upper quartile, follow these steps: 1. **Median:** Since there are 6 numbers, the median will be the average of the 3rd and 4th numbers, which are 35 and 57. \[ \text{Median} = \frac{35 + 57}{2} = \frac{92}{2} = 46 \] 2. **Lower Quartile (Q1):** For an even set of numbers, the lower quartile is the median of the lower half of the data (not including the median if the data set count is odd). The lower half of the data set is 31, 33, 35. Since there are three numbers, the middle one is the median. Thus, the lower quartile is 33. 3. **Upper Quartile (Q3):** Similarly for the upper quartile, which is the median of the upper half of the data, the upper half is 57, 80, 87. Again, because there are three numbers, the middle one is the median of this subset. So, the upper quartile is 80. Therefore, the lower quartile is 33, the median is 46, and the upper quartile is 80.
Statistical Data Analysis
This exercise is about finding the lower quartile, median, and upper quartile of the given set of numbers. The given dataset is already arranged in ascending order: 31, 33, 35, 57, 80, 87. To find the median (which is also the second quartile), we find the middle value of the dataset. Since there are an even number of data points (6 numbers), the median will be the average of the two middle numbers (35 and 57). Median = (35 + 57) / 2 = 92 / 2 = 46 Now, to find the lower quartile (first quartile), we take the median of the lower half of the dataset. The lower half (before the median value) is 31, 33, 35. Since there are three numbers, the middle one is the lower quartile. Lower quartile = 33 To find the upper quartile (third quartile), we take the median of the upper half of the dataset. The upper half (after the median value) is 57, 80, 87. Since there are three numbers here as well, the middle one is the upper quartile. Upper quartile = 80 Therefore, the lower quartile is 33, the median is 46, and the upper quartile is 80.
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