Example Question - calculate roots

Solving Quadratic Equation

确定 a=3，b=5 和 c=-2。 使用二次公式：x = [-b ± √(b²-4ac)] / (2a) 计算 b² - 4ac = 5² - 4×3×(-2) = 25 + 24 = 49 求根 √(b²-4ac) = √49 = 7 代入公式：x = [-5 ± 7] / (2×3) 解得两个解： x1 = (-5 + 7) / 6 = 2 / 6 = 1/3 x2 = (-5 - 7) / 6 = -12 / 6 = -2 所以，方程的解为 x = 1/3 或 x = -2。