Example Question - average speed
Here are examples of questions we've helped users solve.
Calculating Average Speed of Mary's Motorcycle Ride
<p>To find the average speed, we need to calculate the total distance traveled and the total time taken.</p> <p>Total distance = 35 km + 105 km = 140 km</p> <p>Total time = 0.5 hours (30 minutes) + 1.5 hours = 2 hours</p> <p>Average speed = \(\frac{\text{Total distance}}{\text{Total time}}\)</p> <p>Average speed = \(\frac{140 \text{ km}}{2 \text{ hours}} = 70 \text{ km/hour}\)</p>
Calculating Average Speed for Two Distinct Intervals of a Motorcycle Ride
<p>To find the average speed for each of the intervals, we will treat each interval separately, then find the total average speed.</p> <p>For the first interval:</p> <p>Speed = \frac{Distance}{Time} = \frac{35 \text{ km}}{0.5 \text{ hours}} = 70 \text{ km/h}</p> <p>For the second interval:</p> <p>Speed = \frac{105 \text{ km}}{1.5 \text{ hours}} = 70 \text{ km/h}</p> <p>Since the speed in both intervals is the same, the average speed for the entire trip is also 70 km/h.</p>
Calculating Total Distance and Average Speed of a Bus Journey
<p>Let \( d_1 \) be the distance covered in the first 2 hours, and \( d_2 \) be the distance covered in the next 4 hours.</p> <p>Given \( d_1 = 125 \) km and \( d_2 = 240 \) km.</p> <p>The total distance \( D \) covered by the bus is: \( D = d_1 + d_2 \).</p> <p>\( D = 125 \) km \( + 240 \) km.</p> <p>\( D = 365 \) km.</p> <p>Let \( t_1 \) be the time spent during the first part of the journey, and \( t_2 \) be the time spent during the second part.</p> <p>Given \( t_1 = 2 \) hours and \( t_2 = 4 \) hours.</p> <p>The total time \( T \) spent is: \( T = t_1 + t_2 \).</p> <p>\( T = 2 \) hours \( + 4 \) hours.</p> <p>\( T = 6 \) hours.</p> <p>The average speed \( V \) of the bus is calculated as \( V = \frac{D}{T} \).</p> <p>\( V = \frac{365 \text{ km}}{6 \text{ hours}} \).</p> <p>\( V \approx 60.83 \) km/hour.</p>
Calculating Displacement and Average Speed for Multiple Segments of a Journey
The question and the necessary equations are mostly unreadable due to the angle and focus of the image. However, the question seems to relate to the displacement and average speeds of a person, Joseph, traveling from point A to B and back to A. Assuming typical motion problems, the steps would involve calculating the total displacement and dividing it by the total time taken for the journey. To calculate the average speed, one would use: \[ \text{Average Speed} = \frac{\text{Total Distance Traveled}}{\text{Total Time}} \] If the question provided specific distances and times, those values would be plugged into the equation above. Meanwhile, displacement is a vector quantity that depends on the initial and final position. If Joseph returns to point A, the displacement would be zero, as displacement is only concerned with the initial and final positions, not the path traveled.
Calculating the Average Speed of a Student Walking Between Two Points
Given: - Distance from A to B (one direction) is 300 m. - Number of round trips in 20 minutes is 6. The total distance covered for 6 round trips (back and forth) is: \[ 6 \text{ round trips} \times 2 \times 300 \text{ m/round trip} = 3600 \text{ m} \] Time taken for 6 round trips is 20 minutes, converting minutes to seconds: \[ 20 \text{ minutes} \times 60 \text{ seconds/minute} = 1200 \text{ seconds} \] The average speed, \( V \), is total distance divided by total time: \[ V = \frac{\text{Total Distance}}{\text{Total Time}} = \frac{3600 \text{ m}}{1200 \text{ s}} = 3 \text{ m/s} \]
Solving Distance and Average Speed Problem
Bài toán bạn cung cấp trong hình hỏi về quãng đường mà một người đi xe máy từ A đến B và ngược lại. Đây là bài toán về dạng toán chuyển động. Cụ thể, đây là vấn đề về quãng đường và vận tốc trung bình. Dựa trên thông tin trong hình, chúng ta có thể giải bài toán như sau: Ta có công thức tính vận tốc trung bình: V_tb = (S_đi + S_về) / T trong đó, S_đi là quãng đường từ A đến B, S_về là quãng đường từ B về A, và T là tổng thời gian cho cả hai hành trình. Biết rằng quãng đường từ A đến B và từ B về A là như nhau. Gọi S là quãng đường từ A đến B (hoặc từ B về A). Vậy tổng quãng đường: S_đi + S_về = S + S = 2S Thời gian để đi từ A đến B là 3 giờ 20 phút. Đổi 20 phút ra giờ ta được: 20 phút = 20/60 giờ = 1/3 giờ. Vậy tổng thời gian: T = 3 giờ + 1/3 giờ + 3 giờ = 6 1/3 giờ Đổi 6 1/3 giờ ra dạng giờ phù hợp để tính toán dễ dàng hơn: 6 1/3 giờ = 6 + 1/3 = 19/3 giờ Theo đề bài, vận tốc trung bình là 40km/h. Vậy ta có: V_tb = 2S / (19/3) = 40km/h Từ đó ta tìm được quãng đường S: 2S = V_tb * (19/3) 2S = 40 * (19/3) 2S = 760/3 S = (760/3) / 2 S = 760/6 S = 127km Vậy quãng đường từ A đến B là 127km.
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