Question - Probability of Choosing Snacks in Melissa's Pantry
Solution:
The image shows a table with the heading "The table shows the snacks in Melissa's pantry". There are three types of snacks listed in the table with their corresponding amounts:- Granola Bar: 4- Chips: 3- Fruit Snack: 5The question asks: "What is the probability that she chooses a fruit snack, puts it back, and then chooses a granola bar?"To solve this, we calculate the probability for each event and then multiply them together because she is putting the snacks back after choosing, meaning the events are independent.Probability of choosing a fruit snack:The total number of snacks is 4 (Granola Bar) + 3 (Chips) + 5 (Fruit Snack) = 12 snacks.There are 5 fruit snacks, so the probability of choosing a fruit snack is 5/12.Since she puts the fruit snack back, the probabilities for the next choice remain the same.Probability of choosing a granola bar:The total number of snacks is still 12, and there are still 4 granola bars, so the probability of choosing a granola bar is 4/12, which simplifies to 1/3.Therefore, the probability of choosing a fruit snack and then a granola bar (independent events) is:(5/12) * (1/3)Now, let's calculate it:(5/12) * (1/3) = 5/36So the probability that she chooses a fruit snack, puts it back, and then chooses a granola bar is 5/36.
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