Given the equation:
$$9^{2m - 5} \times 9^3 = 9^{m + 1}$$
Combine the left-hand side using the property of exponents:
$$9^{(2m - 5) + 3} = 9^{m + 1}$$
This simplifies to:
$$9^{2m - 2} = 9^{m + 1}$$
Since the bases are the same, set the exponents equal:
$$2m - 2 = m + 1$$
Isolate \( m \):
$$2m - m = 1 + 2$$
$$m = 3$$
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