Solution:
\begin{align*}m\angle EAD + m\angle ADC + m\angle DAB &= 180^\circ \quad \text{(Sum of interior angles of $\triangle ADB$)} \\x + 118^\circ + 30^\circ &= 180^\circ \\x + 148^\circ &= 180^\circ \\x &= 180^\circ - 148^\circ \\x &= 32^\circ\end{align*}