Solution:
Given slope, $$ m = 2 $$, and a point, $$ (1,3) $$, use the point-slope form of the equation of a line: $$ y - y_1 = m(x - x_1) $$.Substitute $$ m = 2 $$, $$ x_1 = 1 $$, and $$ y_1 = 3 $$ into the equation:$$ y - 3 = 2(x - 1) $$Now, simplify and put it in slope-intercept form, $$ y = mx + b $$:$$ y - 3 = 2x - 2 $$$$ y = 2x + 1 $$