Question - Determining Angle Values in Parallel Lines and Transversal Configuration

Since AB is parallel to PQ, by the alternate interior angles theorem:

\( x = 70^\circ \)

Since the sum of angles in a triangle is \( 180^\circ \):

\( x + y + 105^\circ = 180^\circ \)

Substituting the value of \( x \):

\( 70^\circ + y + 105^\circ = 180^\circ \)

\( y = 180^\circ - 175^\circ \)

\( y = 5^\circ \)