Question - Calculating the Time for a Ball to Reach Zero Speed when Thrown Upward

Solution:

To calculate the time for the ball to reach zero speed, we can use the following kinematic equation for uniformly accelerated motion:

\[ v_f = v_i + a \cdot t \]

Where:

\( v_f \) is the final velocity (0 m/s when the ball reaches its maximum height and stops momentarily)

\( v_i \) is the initial velocity (4.5 m/s)

\( a \) is the acceleration (acceleration due to gravity; for a ball thrown upward this is -9.8 m/s\(^2\), since it acts downward)

\( t \) is the time in seconds

We can set \( v_f \) to 0 and solve for \( t \):

\[ 0 = 4.5 \text{ m/s} - (9.8 \text{ m/s}^2) \cdot t \] \[ 9.8 \text{ m/s}^2 \cdot t = 4.5 \text{ m/s} \] \[ t = \frac{4.5 \text{ m/s}}{9.8 \text{ m/s}^2} \] \[ t \approx 0.459 \text{ s} \]

So, the ball will take approximately 0.459 seconds to reach zero speed.

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