Solution:
The image shows a set of numbers in ascending order, and the task is to find the lower quartile, median, and upper quartile of these numbers. Let's calculate each of them:The numbers given are: 13, 23, 34, 37, 45, 47, 52, 56, 58, 66, 81.First, let's find the median, which is the middle number of the data set when arranged in order. Since there are 11 numbers, the median will be the 6th number (as there are 5 numbers on either side of it). So the median is 47.Now let's calculate the lower quartile, which is the median of the lower half of the data set. Exclude the overall median (47) when considering the halves. The lower half of this data set is: 13, 23, 34, 37, 45. The median of this subset is the third number, which is 34, so the lower quartile is 34.Lastly, let's find the upper quartile, which is the median of the upper half of the data set. Again, exclude the overall median (47). The upper half of the data set is: 52, 56, 58, 66, 81. The median of this subset is the third number, which is 58, so the upper quartile is 58.In summary:- The lower quartile is 34.- The median is 47.- The upper quartile is 58.