Question - Calculating Probability of Picking Numbers Without Replacement
Solution:
To solve this problem, we need to determine the probability of picking a 6 first and then a 5 without replacing the first number.The total number of possible numbers to choose from initially is 8 (since we see numbers 2 through 9).The probability of picking a 6 first is:1 out of 8 (since there is only one 6)After picking a 6, there are now 7 numbers left to choose from.The probability of picking a 5 next is:1 out of 7 (since there is only one 5)To find the combined probability of both events occurring (picking a 6 and then a 5), we multiply the probabilities of each individual event:$$ (1/8) * (1/7) = 1/56 $$As a percentage, $$ (1/56) $$ can be calculated as follows:$$ (1/56) * 100 \approx 1.786\% $$Rounding to the nearest tenth, the answer is 1.8%.
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