Question - Angle Calculation in Triangle ABCD
Solution:
\(\angle BDA = 180^\circ - \angle BDC - \angle BAC\)
\(\angle BDA = 180^\circ - 32^\circ - 54^\circ\)
\(\angle BDA = 180^\circ - 86^\circ\)
\(\angle BDA = 94^\circ\)
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