Solution:
It seems that you're requesting help with a math problem involving the coordinates of a quadrilateral. Unfortunately, the image is not clear enough for me to provide a definitive answer, but I can still guide you on how to solve this type of problem.We have a quadrilateral ABCD with points A(2,4), B(4,2), C(-1,-3), and D(3,-1). To answer the questions, you need to:a. Find the slope of each side of quadrilateral ABCD:- The slope of a line through points (x1, y1) and (x2, y2) is given by (y2 - y1) / (x2 - x1).For AB: slope = (2 - 4) / (4 - 2) = -2 / 2 = -1For BC: slope = (-3 - 2) / (-1 - 4) = -5 / -5 = 1For CD: slope = (-1 - (-3)) / (3 - (-1)) = 2 / 4 = 0.5For DA: slope = (4 - (-1)) / (2 - 3) = 5 / -1 = -5b. What type of quadrilateral is formed by the fences? Justify your answer using the slope and/or distance formulas:- To determine the type of quadrilateral, we need to check for parallel sides (equal slopes) and equal lengths (using the distance formula).The distance formula for points (x1, y1) and (x2, y2) is given by √[(x2 - x1)^2 + (y2 - y1)^2].Find the distance of each side:AB = √[(4 - 2)^2 + (2 - 4)^2] = √[2^2 + (-2)^2] = √(4 + 4) = √8BC = √[(-1 - 4)^2 + (-3 - 2)^2] = √[(-5)^2 + (-5)^2] = √(25 + 25) = √50CD = √[(3 - (-1))^2 + (-1 - (-3))^2] = √[4^2 + 2^2] = √(16 + 4) = √20DA = √[(2 - 3)^2 + (4 - (-1))^2] = √[(-1)^2 + 5^2] = √(1 + 25) = √26The sides AB and CD are not parallel (their slopes are not equal), and sides BC and DA are also not parallel. Also, none of the side lengths are equal.Without plotting the points, we can't be entirely certain what specific type of quadrilateral it is, but we can confirm that it is not a parallelogram, rectangle, square, or rhombus since none of the sides are equal in length or parallel. It's most likely a general quadrilateral with no special properties regarding its sides or angles.Keep in mind that the calculations for the distances of sides AB, BC, CD, and DA should be recalculated with proper care for precision and to ensure accuracy in the answer. If the points were plotted on a graph, the shape could also be visually identified and confirmed.