9 = 3 + x/4 9 - 3 = x/4 6 = x/4 x = 6 * 4 x = 24
The equation in the image is \( e^{x - 7} + 11 = 20 \). To solve for \( x \), we want to isolate the term containing \( x \). Here are the steps: 1. Subtract 11 from both sides of the equation to get the exponential term by itself: \( e^{x - 7} = 20 - 11 \) \( e^{x - 7} = 9 \) 2. Take the natural logarithm (ln) of both sides to 'undo' the exponential. Since \( \ln(e^y) = y \), we have: \( \ln(e^{x - 7}) = \ln(9) \) \( x - 7 = \ln(9) \) 3. Add 7 to both sides to solve for \( x \): \( x = \ln(9) + 7 \) Now we have the solution for \( x \). If a specific numerical value is required, you'd compute \( \ln(9) \) using a calculator and then add 7 to that result.
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