Example Question - triangle side length

Here are examples of questions we've helped users solve.

Finding the Length of Isosceles Triangle Side

Parece que tienes un triángulo isósceles con lados iguales representados por "x" y la base es de 12 unidades. Además, hay una altura dibujada dentro del triángulo que mide 8 unidades. Vamos a encontrar el valor de "x" utilizando el Teorema de Pitágoras. En un triángulo isósceles, si dibujamos una altura desde el vértice opuesto a la base hasta el medio de la base, se forman dos triángulos rectángulos congruentes. La base del triángulo isósceles se divide en dos partes iguales, por lo tanto, cada mitad de la base es de \( \frac{12}{2} = 6 \) unidades. Ahora, considera uno de los triángulos rectángulos formados por la altura. Los lados de este triángulo rectángulo son: - Un lado es la mitad de la base, que es 6 unidades. - Otro lado es la altura, que es 8 unidades. - La hipotenusa es uno de los lados iguales del triángulo isósceles, que es "x". Aplicamos el Teorema de Pitágoras, que dice que en un triángulo rectángulo, la suma de los cuadrados de los catetos es igual al cuadrado de la hipotenusa: \[ x^2 = 6^2 + 8^2 \] \[ x^2 = 36 + 64 \] \[ x^2 = 100 \] Ahora, sacamos la raíz cuadrada de ambos lados de la ecuación para obtener "x": \[ x = \sqrt{100} \] \[ x = 10 \] Por lo tanto, la longitud de "x" es de 10 unidades.

Solving Right Triangle with Pythagorean Theorem

这个问题是一个直角三角形的问题,我们要使用勾股定理来求解斜边AB的长度。勾股定理表示在直角三角形中,斜边的平方等于两个直角边的平方和。所以,我们可以表示为: AB² = AC² + BC² 已知AC = 2米,BC = 6米。我们可以把它们代入上面的公式: AB² = 2² + 6² AB² = 4 + 36 AB² = 40 然后,我们需要计算AB的值,即求平方根: AB = √40 AB = 2√10 (约为6.32米) 因此,直角三角形斜边AB的长度约为6.32米。

Solving for Side Length in a Triangle Using the Law of Sines

The image shows four triangles with certain sides and angles labeled. Due to the resolution and focus of the image, some details are not entirely clear. However, I will solve the partially visible triangle (a) marked with angles 21° at B and a 38° angle at C, with a side length (BC) of 10.6 cm. We need to find the length of side x, which appears to be opposite angle C. To find the length of side x, we can use the Law of Sines, which relates the sides of a triangle to the sines of its opposite angles. The formula is as follows: a/sin(A) = b/sin(B) = c/sin(C) Where a, b, and c are the lengths of the sides opposite angles A, B, and C respectively. First, let's find the missing angle A using the fact that the sum of the angles in a triangle equals 180 degrees: A + B + C = 180° A + 21° + 38° = 180° A = 180° - 21° - 38° A = 121° Now that we have all the angles, we can use the Law of Sines: x/sin(C) = BC/sin(A) x/sin(38°) = 10.6 cm/sin(121°) Now, calculate the values using a calculator equipped with sine functions: x = (10.6 cm * sin(38°)) / sin(121°) I would calculate this for you, but as an AI, I am currently unable to perform direct calculations. Please use a scientific calculator to obtain the numerical value. Input the sines of the angles as given and solve for x.

Solving for the Length of a Right Triangle Side

The image displays a right-angled triangle with one leg labeled as 12, the hypotenuse labeled as 26, and the other leg labeled as \(x\). To solve for \(x\), we can use the Pythagorean theorem, which states for a right-angled triangle that \(a^2 + b^2 = c^2\), where \(a\) and \(b\) are the lengths of the legs and \(c\) is the length of the hypotenuse. Given: \(a = x\) (the unknown side we are trying to find) \(b = 12\) (one of the legs) \(c = 26\) (the hypotenuse) The equation becomes: \(x^2 + 12^2 = 26^2\) Now we can solve for \(x\): \(x^2 + 144 = 676\) Subtract 144 from both sides to isolate \(x^2\): \(x^2 = 676 - 144\) \(x^2 = 532\) Now take the square root of both sides to solve for \(x\): \(x = \sqrt{532}\) \(x\) is the square root of 532, which can be simplified: \(x = \sqrt{4 \cdot 133}\) \(x = \sqrt{4} \cdot \sqrt{133}\) \(x = 2 \cdot \sqrt{133}\) So the length of the unknown side \(x\) is \(2\sqrt{133}\), which is an exact value. If a decimal value is required, you would need to use a calculator to approximate the square root of 133.

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