Example Question - subtraction of fractions
Here are examples of questions we've helped users solve.
Solving Linear Equation with Fractions
To solve the given equation: \[ 5x + \frac{2}{3} = \frac{7}{6} \] You want to solve for x. Follow these steps: 1. Subtract \( \frac{2}{3} \) from both sides of the equation to isolate the term with x on one side. \[ 5x + \frac{2}{3} - \frac{2}{3} = \frac{7}{6} - \frac{2}{3} \] 2. Calculate the right side, finding a common denominator for \( \frac{7}{6} \) and \( \frac{2}{3} \). The common denominator is 6, so: \[ \frac{7}{6} - \frac{2}{3} = \frac{7}{6} - \frac{4}{6} \] Subtract the numerators: \[ \frac{7 - 4}{6} = \frac{3}{6} \] Simplify \( \frac{3}{6} \) to \( \frac{1}{2} \). So now you have: \[ 5x = \frac{1}{2} \] 3. To find x, divide both sides of the equation by 5: \[ x = \frac{1}{2} \div 5 \] \[ x = \frac{1}{2} \times \frac{1}{5} \] \[ x = \frac{1}{10} \] So, the solution to the equation is: \[ x = \frac{1}{10} \]
Subtraction of Fractions with Common Denominator
It looks like the image shows a mathematical expression, "\(\frac{1}{80} - 0.90\)". To solve this, we first need to convert the decimal to a fraction so that we have common denominators. The decimal 0.90 is equivalent to the fraction \(\frac{90}{100}\). We can simplify this fraction by dividing both the numerator and the denominator by 10, which gives us \(\frac{9}{10}\). Now, to subtract \(\frac{9}{10}\) from \(\frac{1}{80}\), we need a common denominator. The least common denominator of 80 and 10 is 80. Let's convert \(\frac{9}{10}\) to a fraction with a denominator of 80: \(\frac{9}{10} = \frac{9 \times 8}{10 \times 8} = \frac{72}{80}\). Now that we have both fractions with a common denominator, we can subtract them: \(\frac{1}{80} - \frac{72}{80} = \frac{1 - 72}{80} = \frac{-71}{80}\). The final result is \(-\frac{71}{80}\).
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