Probability of Spinner Outcomes
The image shows three spinners, and the question asks what the probability is that the first spinner will land on A, the second spinner will land on an even number, and the third spinner will land on Blue.
For Spinner 1, there appears to be two outcomes (A and B), so the probability that it will land on A is 1 out of 2.
For Spinner 2, there are four outcomes (1, 2, 3, 4), and two of them are even (2 and 4), so the probability that it will land on an even number is 2 out of 4, which simplifies to 1 out of 2.
For Spinner 3, there appears to be three outcomes (Blue, Red, and Green), so the probability that it will land on Blue is 1 out of 3.
To find the overall probability of all three independent events happening, we multiply the probabilities together:
(1/2) * (1/2) * (1/3) = 1/12.
Therefore, the probability that the first spinner will land on A, the second spinner will land on an even number, and the third spinner will land on Blue is 1/12. The correct answer is option c.
