Example Question - significant figures
Here are examples of questions we've helped users solve.
Finding the Significant Figures in a Number
<p>Pertama, kita perlu faham definisi angka bererti (atau significant figures dalam Bahasa Inggeris). Angka bererti adalah angka yang memberikan makna bagi resolusi pengukuran. Untuk bilangan 3 700, terdapat dua angka bererti, iaitu 3 dan 7, kerana nombor-nombor seterusnya (0 di dalam kes ini) berfungsi sebagai penunjuk kedudukan angka bererti dan tidak dianggap sebagai angka bererti jika tiada nombor lain selepasnya yang tidak sifar.</p> <p>Maka, bilangan angka bererti bagi nombor 3 700 adalah 2.</p>
Significant Figures Calculation in Mathematics
The image shows a mathematics question paper with the first question asking to express the number 0.0000407 to two significant figures. To express the number to two significant figures, we need to consider the first two non-zero digits. In this case, the first two non-zero digits are '4' and '0'. However, since the '0' is not significant in this context (it doesn't add any value after the '4'), we only consider '4' as the significant digit. Thus, we need to round the number 0.0000407 to the place of the '4'. The '4' is in the ten-thousandths place, and the digit right after the '4' is '0', so there is no need to round up. Thus, we get 0.00004 (option b). Therefore, the correct answer to question 1 is: (b) 0.00004
Calculating Upper and Lower Bounds of Chemical Mass
The image contains the following question: "At the start of an experiment, some chemicals had a mass of 62 g, rounded to 2 significant figures. During the experiment, the mass of the chemicals decreased by 7.3 g, rounded to 2 significant figures. Calculate the lower and upper bounds of the mass of the chemicals at the end of the experiment." To solve this, we need to calculate the upper and lower bounds considering the number of significant figures the values were rounded to. For the starting mass 62 g rounded to 2 significant figures, the lower bound would be one half unit of the last significant digit less than 62 g, and the upper bound would be one half unit of the last significant digit more than 62 g. Since the last significant digit is in the tens place, a half unit is 0.5 tens, which is 5 g. Lower bound of the starting mass = 62 g - 5 g = 57 g Upper bound of the starting mass = 62 g + 5 g = 67 g For the decrease in mass 7.3 g rounded to 2 significant figures, the last significant figure is in the tenths place, so one half of the last significant digit is 0.05 g. Lower bound of the decrease in mass = 7.3 g - 0.05 g = 7.25 g Upper bound of the decrease in mass = 7.3 g + 0.05 g = 7.35 g To find the bounds of the mass of the chemicals at the end of the experiment, subtract the calculated decrease bounds from the calculated mass bounds: Lower bound at end = Lower bound of starting mass - Upper bound of decrease in mass Upper bound at end = Upper bound of starting mass - Lower bound of decrease in mass Lower bound at end = 57 g - 7.35 g = 49.65 g Upper bound at end = 67 g - 7.25 g = 59.75 g So, the lower and upper bounds of the mass of the chemicals at the end of the experiment are 49.65 g and 59.75 g, respectively.
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