Profit Calculation from Sale of Articles
<p>The image shows a handwritten question about profit calculation.</p>
<p>Let's denote:</p>
<p>\( CP \) = Cost Price</p>
<p>\( SP \) = Selling Price</p>
<p>Given that the seller sells one article for \( \$6000 \) and a loss \( SP = CP - \frac{CP}{7} \).</p>
<p>We then express \( SP \) in terms of \( CP \):</p>
<p>\( SP = CP - \frac{CP}{7} \)</p>
<p>\( SP = \frac{6CP}{7} \)</p>
<p>Now, if the seller sells another article for \( \$7000 \) with a profit of \( SP = CP + \frac{CP}{7} \),</p>
<p>We express this \( SP \) in terms of \( CP \):</p>
<p>\( SP = CP + \frac{CP}{7} \)</p>
<p>\( SP = \frac{8CP}{7} \)</p>
<p>Now we have two equations:</p>
<p>1) \( \frac{6CP}{7} = 6000 \)</p>
<p>2) \( \frac{8CP}{7} = 7000 \)</p>
<p>We can now solve for \( CP \) from either equation, but equation 1) is simpler:</p>
<p>\( CP = \frac{6000 \times 7}{6} \)</p>
<p>\( CP = 7000 \times \frac{7}{6} \)</p>
<p>\( CP = \$7000 \)</p>
<p>Now, find the total profit when he sells both articles:</p>
<p>The profit from selling the second item is \( \$7000 \) with a profit of \( \frac{CP}{7} \):</p>
<p>\( Profit = \frac{CP}{7} \)</p>
<p>\( Profit = \frac{7000}{7} \)</p>
<p>\( Profit = \$1000 \)</p>
<p>Since he sells the first item at a loss of \( \frac{CP}{7} \), which is \( \$1000 \), and the second one at a profit of \( \$1000 \), the total profit is:</p>
<p>\( Total\,Profit = Profit\,from\,second\,item - Loss\,from\,first\,item \)</p>
<p>\( Total\,Profit = \$1000 - \$1000 \)</p>
<p>\( Total\,Profit = \$0 \)</p>
<p>Therefore, the seller neither makes a profit nor incurs a loss overall.</p>
