Example Question - net force
Here are examples of questions we've helped users solve.
Determining the State of Motion Based on Applied and Frictional Forces
The net force \( F_{net} \) on the object is given by the difference between the applied force \( F_{applied} \) and the frictional force \( F_{friction} \). Given: \( F_{applied} = 20 \, \text{N} \) \( F_{friction} = 20 \, \text{N} \) Calculating the net force: \( F_{net} = F_{applied} - F_{friction} \) \( F_{net} = 20 \, \text{N} - 20 \, \text{N} \) \( F_{net} = 0 \, \text{N} \) Since the net force on the object is zero, according to Newton's First Law, the object will remain at rest. Therefore, the state of motion of the object will be at rest.
Calculating Acceleration With Friction
The net force on the block is the difference between the applied force and the frictional force. Net force = Applied force - Frictional force Net force = 25 N - 15 N Net force = 10 N To find the acceleration (a), use Newton's second law, \( F = ma \), where F is the net force and m is the mass. Solving for acceleration \( a \), \( a = \frac{F}{m} \) Substitute the known values into the equation, \( a = \frac{10 \, \text{N}}{5 \, \text{kg}} \) The acceleration of the block is \( 2 \, \text{m/s}^2 \).
Calculating Acceleration of an Object
The image you've provided includes a question which states: "Solve the following word problem. 1. If a 4 kg object experiences a net force of 12 N, what will be the object's acceleration?" To solve this problem, we'll use Newton's Second Law of Motion, which is defined as: F = ma where F is the net force applied to the object, m is the mass of the object, and a is the acceleration of the object. We are given: F (net force) = 12 N m (mass) = 4 kg We need to find the acceleration (a). Firstly, we rearrange the equation to solve for acceleration: \( a = \frac{F}{m} \) Now we can substitute in the values we have: \( a = \frac{12 \text{ N}}{4 \text{ kg}} \) Now doing the calculation: \( a = 3 \text{ m/s}^2 \) The object's acceleration would be 3 meters per second squared.
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