The image shows a multiplication operation: \( 23 \times 4 \). To solve this, multiply each digit of 23 by 4, starting from the rightmost digit: \( 3 \times 4 = 12 \) (write down 2 and carry over the 1) \( 2 \times 4 = 8 \) and add the carried over 1, which is \( 8 + 1 = 9 \) So, the final result is \( 23 \times 4 = 92 \).
The image shows a multiplication problem: 51 times 5. To solve this, you can multiply each digit of 51 by 5, starting from the rightmost digit: \( 1 \times 5 = 5 \) \( 5 \times 5 = 25 \) Combine the results, placing the digit from the ones place (5) down and carrying over anything from the tens place (2) to add to the next multiplication result: So we have 5 (from the 1 × 5) and 25 (from the 5 × 5, which becomes 2 carried over and 5 written down). Putting it together: \( 2 \) (carried over) \( \times 51 \) \( \times \ \ \ 5 \) ------------ \( \ \ \ 255 \) The answer is 255.
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