Example Question - irregular figure
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Calculating Area of Irregular Figure Using Rectangles
To find the area of the irregular figure drawn in the image, we can split it into simpler shapes, such as rectangles, compute their areas, and then sum these areas. The figure can be split into three rectangles labeled A, B, and C in the image. Here's how to calculate each rectangle's area: - Rectangle A has a width of 4m. To find its height, we subtract the width of Rectangle C (which is 8m) from the total width of the structure (which is 12m). This gives us 12m - 8m = 4m. Therefore, the area of Rectangle A is 4m x 4m = 16m². - Rectangle B is directly beneath Rectangle A, sharing the width of 4m, and stretches across the entire height of the structure, which is 8m. Therefore, the area of Rectangle B is 4m x 8m = 32m². - Rectangle C has a width of 8m and also stretches across the entire height of the structure, 8m. Its area is 8m x 8m = 64m². Finally, we sum the areas of Rectangles A, B, and C to get the total area of the figure: Total area = Area of A + Area of B + Area of C Total area = 16m² + 32m² + 64m² Total area = 112m² So, the area of the irregular figure is 112 square meters.
Calculating Area of an Irregular Figure
To solve for the area of the irregular figure in the image, you need to break it down into simpler shapes whose area you can calculate easily, and then sum those areas. There's a central rectangle, and two squares extending from it: 1. The central rectangle's dimensions appear to be 15m in length and 5m in width. 2. The two squares extending from the sides of the rectangle are both 5m x 5m. Calculating the area of each: 1. Area of the central rectangle = length × width = 15m × 5m = 75 square meters. 2. Area of each of the squares = side × side = 5m × 5m = 25 square meters. Since there are two such squares, you'll multiply one of their areas by 2: Area of the two squares combined = 25 square meters × 2 = 50 square meters. Finally, add the areas of the central rectangle and the two squares: Total area = Area of the rectangle + Area of the two squares = 75 square meters + 50 square meters = 125 square meters. Therefore, the area of the irregular figure is 125 square meters.
Calculating Area of Irregular Figure with Rectangles
The image shows calculations made to find the area of an irregular figure that is composed of two rectangles, labeled A and B. However, there seems to be a mistake in the calculations presented in the image. Let me guide you through the correct process to find the total area. Firstly, to find the area of each part of the irregular figure, you need to multiply the width by the height of each rectangle. For rectangle A: - The width is given as 6 meters. - The height is given as 18 meters. So, the area of A will be 6 meters x 18 meters = 108 square meters. For rectangle B: - The width is not directly given; however, B is an extension of A, which makes B's full length equal to the length of A (18 meters) plus the additional length equal to the width of A (6 meters). - Thus, B's length is 18 m + 6 m = 24 meters. - The height of B is given as 18 meters. So, the area of B will be 24 meters x 18 meters = 432 square meters. Add the area of A and B to find the total area of the irregular shape: Area of A + Area of B = 108 square meters + 432 square meters = 540 square meters. The correct answer is 540 square meters for the area of the entire irregular figure.
Calculating Area of an Irregular Figure using Rectangles
To find the area of the irregular figure, we can divide the figure into two rectangles, label them A and B as in the image, and then calculate the area for each one before summing them up. The given dimensions for Rectangle A are 6m (height) and 9m (width). The area of Rectangle A = height * width = 6m * 9m = 54m² Rectangle B overlaps with Rectangle A, but from the image, we can deduce that Rectangle B extends beyond Rectangle A by 6 m (since the height of A is 6 m, and they share a common width segment). The total width of Rectangle B is given as 18 m. Therefore, to avoid counting the overlapped area twice, we calculate the area of the extension of Rectangle B. The width of the extension of Rectangle B = total width - width of Rectangle A = 18m - 9m = 9m Using the height of Rectangle A as the height of Rectangle B (since the heights are the same): The area of the extension of Rectangle B = height * extended width = 6m * 9m = 54m² Finally, we add the areas of Rectangle A and the extension of Rectangle B together to find the total area of the irregular shape: Total area = area of A + area of B's extension = 54m² + 54m² = 108m² So, the area of the irregular figure is 108 square meters.
Calculating Total Area of an Irregular Figure
Absolutely, let's break the irregular figure into two rectangular areas (A and B) to find the total area. For rectangle A: - The length is 6 meters. - The width is 18 meters. The area of rectangle A (A_A) is length times width: A_A = 6m * 18m = 108m². For rectangle B, we see it's a square because all sides are equal: - The side length is 18 meters. The area of rectangle B (A_B) is side length squared: A_B = 18m * 18m = 324m². To find the total area (A_total) of the irregular figure, we add the areas of both rectangles: A_total = A_A + A_B A_total = 108m² + 324m² A_total = 432m². Therefore, the area of the irregular figure is 432 square meters.
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