Solving a Fraction Expression
The image is a bit blurry, but it looks like the expression is a fraction where the numerator is \( \frac{1}{7x^2y^3} \) and the denominator is \( \frac{1}{3x^3y} \).
To solve this expression, you can simply invert the denominator and multiply it with the numerator:
\( (\frac{1}{7x^2y^3}) \times (\frac{3x^3y}{1}) \)
When you multiply fractions, you multiply the numerators together and the denominators together:
\( \frac{1 \times 3x^3y}{7x^2y^3 \times 1} \)
\( \frac{3x^3y}{7x^2y^3} \)
Now simplify by canceling out the common terms:
The \( x^2 \) in the denominator cancels out with two of the \( x \)s in the numerator, leaving you with one \( x \) in the numerator. Similarly, the \( y \) in the numerator and one \( y \) in the denominator will cancel out, leaving you with \( y^2 \) in the denominator.
So, you're left with:
\( \frac{3x}{7y^2} \)
This is the simplified form of the given expression.
