<p>The question asks to find the hypotenuse \( c \) of a right triangle with legs \( a = 3 \) and \( b = 4 \).</p> <p>We use the Pythagorean theorem: \( a^2 + b^2 = c^2 \).</p> <p>Substitute the given values: \( 3^2 + 4^2 = c^2 \).</p> <p>Calculate the squares: \( 9 + 16 = c^2 \).</p> <p>Add the results: \( 25 = c^2 \).</p> <p>Take the square root of both sides: \( \sqrt{25} = \sqrt{c^2} \).</p> <p>Thus, \( c = 5 \).</p>
The triangle in the image appears to be a right triangle, with sides of length 8 and 13, and we are asked to solve for the hypotenuse x. You can use the Pythagorean theorem to solve for x, which is: a^2 + b^2 = c^2 where a and b are the lengths of the legs of the right triangle, and c is the length of the hypotenuse. For this triangle, we will have: 8^2 + 13^2 = x^2 Now, calculating the squares: 64 + 169 = x^2 233 = x^2 Now, take the square root of both sides: √233 = x x ≈ 15.3 So, to the nearest tenth, x is approximately 15.3.
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