Example Question - frictional force
Here are examples of questions we've helped users solve.
Determining the State of Motion for an Object on a Surface
<p>Let F_{applied} be the applied force.</p> <p>Let F_{frictional} be the frictional force.</p> <p>Since F_{applied} = F_{frictional},</p> <p>There is no net force acting on the object (F_{net} = F_{applied} - F_{frictional} = 0 N),</p> <p>Thus, according to Newton's first law of motion, the object will remain at rest.</p>
Determining the State of Motion Based on Applied and Frictional Forces
The net force \( F_{net} \) on the object is given by the difference between the applied force \( F_{applied} \) and the frictional force \( F_{friction} \). Given: \( F_{applied} = 20 \, \text{N} \) \( F_{friction} = 20 \, \text{N} \) Calculating the net force: \( F_{net} = F_{applied} - F_{friction} \) \( F_{net} = 20 \, \text{N} - 20 \, \text{N} \) \( F_{net} = 0 \, \text{N} \) Since the net force on the object is zero, according to Newton's First Law, the object will remain at rest. Therefore, the state of motion of the object will be at rest.
Calculating Acceleration With Friction
The net force on the block is the difference between the applied force and the frictional force. Net force = Applied force - Frictional force Net force = 25 N - 15 N Net force = 10 N To find the acceleration (a), use Newton's second law, \( F = ma \), where F is the net force and m is the mass. Solving for acceleration \( a \), \( a = \frac{F}{m} \) Substitute the known values into the equation, \( a = \frac{10 \, \text{N}}{5 \, \text{kg}} \) The acceleration of the block is \( 2 \, \text{m/s}^2 \).
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